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A particle moves in a circular path such...

A particle moves in a circular path such that its speed v varies with distance as `v = alpha sqrt(s)` where `alpha` is a positive constant. Find the acceleration of paarticle after trafversing a distance S?

A

`alpha^(2)sqrt((1)/(4)-(S^(2))/(R^(2)))`

B

`alpha^(2)sqrt((1)/(4)+(S^(2))/(R^(2)))`

C

`alpha sqrt((1)/(2)+(S^(2))/(R^(2)))`

D

`alpha^(2) sqrt((1)/(2)+(S^(2))/(R^(2)))`

Text Solution

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The correct Answer is:
B
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