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A clock with an iron pendulum keeps corr...

A clock with an iron pendulum keeps correct time at `20^(@)C`. How much time will it lose or gain in a day if the temperature changes to `40^(@)C`. Thermal coefficient of liner expansion `alpha = 0.000012 per^(@)C`.

A

10.368 sec gain

B

10.368 sec loss

C

5.184 sec gain

D

5.184 sec loss

Text Solution

Verified by Experts

The correct Answer is:
B

`T= 2pi sqrt((L)/(g))`
and `T.=2pi sqrt((L.)/(g))`
or `(T.)/(T)= sqrt((L.)/(L))`
`L.= L(1 xx alpha Delta t)`
`:.alpha=(gamma)/(3) = (36xx10^(-6))/(3)`
`=L(1+12 xx 10^(-6)xx20) = 12xx10^(-6)""^(@)C^(-1)`
`L.= L(1.00024)`
`(T.)/(T)= sqrt((1.00024L)/(L))`
or `(T.)/(2)= 1.00012 " "( :.T=2sec)`
`T.=2.00024`
Loss in time per day `=((2.00024-2) xx 24xx60xx60)/(2) sec. `
= 10.368 sec. Loss/day
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