The treatment of `CH_(3) MgX ` with `CH_(3)-C-=C-H` produces :

Options

A. `CH_(3)-CH=CH_(2)`
B. `CH_(3)-C -=C-CH_(3)`
C. `CH_(3)- overset(H)overset(|)C=overset(H)overset(|)C-CH_(3)`
D. `CH_(4)`

Explanation

To solve the question regarding the treatment of `CH₃MgX` with `CH₃-C≡C-H`, we need to analyze the reaction between a Grignard reagent and a terminal alkyne. Here’s a step-by-step breakdown of the process:

### Step 1: Identify the reactants
The reactants in this reaction are:
- Grignard reagent: `CH₃MgX` (where X is a halogen)
- Terminal alkyne: `CH₃-C≡C-H`

### Step 2: Understand the nature of the Grignard reagent
Grignard reagents are highly reactive organomagnesium compounds. They act as nucleophiles due to the presence of a carbon atom with a partial negative charge (C⁻) and a magnesium atom with a partial positive charge (Mg²⁺).

### Step 3: React the Grignard reagent with the terminal alkyne
When `CH₃MgX` reacts with `CH₃-C≡C-H`, the nucleophilic carbon (C⁻) from the Grignard reagent will attack the hydrogen (H⁺) of the terminal alkyne. This results in the formation of a new bond.

### Step 4: Formation of products
1. The carbon atom from the Grignard reagent (C⁻) will bond with the hydrogen atom (H⁺) from the terminal alkyne, forming methane (CH₄).
2. The remaining alkyne will now have a negative charge on the carbon that was previously bonded to the hydrogen, resulting in the formation of `CH₃-C≡C-MgX`.

### Step 5: Write the final products
The final products of this reaction are:
- Methane (CH₄)
- `CH₃-C≡C-MgX`

### Conclusion
Therefore, the treatment of `CH₃MgX` with `CH₃-C≡C-H` produces methane and `CH₃-C≡C-MgX`.