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One day a labourer earned Rs. 58""1/2. O...

One day a labourer earned Rs. `58""1/2`. Out of this money, he spent Rs. `18""3/4` on food and Rs. `6""1/5` on other needs. How much is left with him?

A

Rs. `43""15/20`

B

Rs. `25""17/23`

C

Rs. `33""11/20`

D

Rs. `45""9/20`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow these instructions: ### Step 1: Convert Mixed Numbers to Improper Fractions 1. **Total money earned by the laborer**: Rs. 58 1/2 - Convert to improper fraction: \[ 58 \times 2 + 1 = 116 + 1 = 117 \quad \text{so,} \quad \frac{117}{2} \] 2. **Money spent on food**: Rs. 18 3/4 - Convert to improper fraction: \[ 18 \times 4 + 3 = 72 + 3 = 75 \quad \text{so,} \quad \frac{75}{4} \] 3. **Money spent on other needs**: Rs. 6 1/5 - Convert to improper fraction: \[ 6 \times 5 + 1 = 30 + 1 = 31 \quad \text{so,} \quad \frac{31}{5} \] ### Step 2: Find Total Money Spent 1. **Add the amounts spent on food and other needs**: \[ \text{Total money spent} = \frac{75}{4} + \frac{31}{5} \] 2. **Find the LCM of the denominators (4 and 5)**: - The LCM of 4 and 5 is 20. 3. **Convert the fractions to have a common denominator**: - For \(\frac{75}{4}\): \[ \frac{75 \times 5}{4 \times 5} = \frac{375}{20} \] - For \(\frac{31}{5}\): \[ \frac{31 \times 4}{5 \times 4} = \frac{124}{20} \] 4. **Add the fractions**: \[ \frac{375}{20} + \frac{124}{20} = \frac{375 + 124}{20} = \frac{499}{20} \] ### Step 3: Calculate Money Left 1. **Subtract the total money spent from the total money earned**: \[ \text{Money left} = \frac{117}{2} - \frac{499}{20} \] 2. **Find the LCM of the denominators (2 and 20)**: - The LCM of 2 and 20 is 20. 3. **Convert \(\frac{117}{2}\) to have a common denominator**: \[ \frac{117 \times 10}{2 \times 10} = \frac{1170}{20} \] 4. **Now subtract the fractions**: \[ \frac{1170}{20} - \frac{499}{20} = \frac{1170 - 499}{20} = \frac{671}{20} \] ### Step 4: Convert to Mixed Number 1. **Convert \(\frac{671}{20}\) to a mixed number**: - Divide 671 by 20: - 20 goes into 671 thirty-three times (33). - Remainder: \(671 - 660 = 11\). - So, \(\frac{671}{20} = 33 \frac{11}{20}\). ### Final Answer The amount left with the laborer is Rs. \(33 \frac{11}{20}\). ---
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