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From a rope of length 20""1/2 m, a piece...

From a rope of length `20""1/2` m, a piece of length `3""5/8` m is cut off. Find the length of the remaining rope.

A

`16""7/8` m

B

`9""5/8` m

C

`15""3/8` m

D

`19""5/9` m

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the length of the remaining rope after cutting off a piece, we can follow these steps: ### Step-by-Step Solution: 1. **Convert the lengths to improper fractions:** - The total length of the rope is given as \(20 \frac{1}{2}\) m. - Convert this to an improper fraction: \[ 20 \frac{1}{2} = \frac{20 \times 2 + 1}{2} = \frac{40 + 1}{2} = \frac{41}{2} \text{ m} \] - The length of the piece cut off is \(3 \frac{5}{8}\) m. - Convert this to an improper fraction: \[ 3 \frac{5}{8} = \frac{3 \times 8 + 5}{8} = \frac{24 + 5}{8} = \frac{29}{8} \text{ m} \] 2. **Set up the equation for the remaining length:** - Let \(D\) be the length of the remaining rope. - The equation will be: \[ D = \text{Total Length} - \text{Cut Off Length} \] - Substituting the values we have: \[ D = \frac{41}{2} - \frac{29}{8} \] 3. **Find a common denominator:** - The denominators are 2 and 8. The least common multiple (LCM) of 2 and 8 is 8. - Convert \(\frac{41}{2}\) to have a denominator of 8: \[ \frac{41}{2} = \frac{41 \times 4}{2 \times 4} = \frac{164}{8} \] 4. **Subtract the fractions:** - Now we can subtract: \[ D = \frac{164}{8} - \frac{29}{8} = \frac{164 - 29}{8} = \frac{135}{8} \] 5. **Convert the improper fraction back to a mixed number:** - To convert \(\frac{135}{8}\) to a mixed number, divide 135 by 8: \[ 135 \div 8 = 16 \quad \text{(whole number part)} \] - The remainder is: \[ 135 - (16 \times 8) = 135 - 128 = 7 \] - Therefore, \[ \frac{135}{8} = 16 \frac{7}{8} \text{ m} \] ### Final Answer: The length of the remaining rope is \(16 \frac{7}{8}\) m.
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