Find the value of :
`2x^(2)-3x+4` where x=2

Answer

To find the value of the expression \(2x^2 - 3x + 4\) where \(x = 2\), we will substitute \(2\) for \(x\) in the expression and then simplify step by step.

### Step 1: Substitute \(x = 2\) into the expression
We start with the expression:
\[ 2x^2 - 3x + 4 \]
Now, substituting \(x = 2\):
\[ 2(2)^2 - 3(2) + 4 \]

### Step 2: Calculate \(2^2\)
Calculate \(2^2\):
\[ 2^2 = 4 \]
Now substitute this value back into the expression:
\[ 2(4) - 3(2) + 4 \]

### Step 3: Multiply \(2\) by \(4\)
Now calculate \(2 \times 4\):
\[ 2 \times 4 = 8 \]
So the expression now looks like:
\[ 8 - 3(2) + 4 \]

### Step 4: Calculate \(3 \times 2\)
Now calculate \(3 \times 2\):
\[ 3 \times 2 = 6 \]
Substituting this back gives us:
\[ 8 - 6 + 4 \]

### Step 5: Perform the subtraction and addition
Now, we perform the operations from left to right:
First, subtract \(6\) from \(8\):
\[ 8 - 6 = 2 \]
Now add \(4\):
\[ 2 + 4 = 6 \]

### Final Result
Thus, the value of the expression \(2x^2 - 3x + 4\) when \(x = 2\) is:
\[ \boxed{6} \]