If x = 2, y = 3 and z = -1, find the values of :
`(2x-3y+4z)/(3x-z)`

Answer

To solve the expression \((2x - 3y + 4z) / (3x - z)\) given the values \(x = 2\), \(y = 3\), and \(z = -1\), we will follow these steps:

### Step 1: Substitute the values of \(x\), \(y\), and \(z\) into the expression.

We have:
- \(x = 2\)
- \(y = 3\)
- \(z = -1\)

Now, we substitute these values into the expression:

\[ \frac{(2(2) - 3(3) + 4(-1))}{(3(2) - (-1))} \]

### Step 2: Calculate the numerator.

First, we calculate the numerator \(2(2) - 3(3) + 4(-1)\):

\[ = 4 - 9 - 4 \]

Now, simplify this:

\[ = 4 - 9 = -5 \]
\[ -5 - 4 = -9 \]

So, the numerator is \(-9\).

### Step 3: Calculate the denominator.

Next, we calculate the denominator \(3(2) - (-1)\):

\[ = 6 + 1 \]

Now, simplify this:

\[ = 7 \]

So, the denominator is \(7\).

### Step 4: Combine the results.

Now, we can combine the results of the numerator and denominator:

\[ \frac{-9}{7} \]

### Final Answer:

Thus, the value of the expression \((2x - 3y + 4z) / (3x - z)\) is:

\[ \frac{-9}{7} \]

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