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Consider the expression (3)/(2)x^(2)y-(1...

Consider the expression `(3)/(2)x^(2)y-(1)/(2)xy^(2)+6x^(2)y^(2)`
How many ters are there ? What do you cell such an expression?

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The correct Answer is:
To solve the question, we will analyze the given expression step by step. ### Step 1: Identify the expression The expression given is: \[ \frac{3}{2}x^2y - \frac{1}{2}xy^2 + 6x^2y^2 \] ### Step 2: Count the terms A term in an algebraic expression is a part that is separated by a plus (+) or minus (−) sign. In our expression, we can identify the terms as follows: 1. \(\frac{3}{2}x^2y\) (first term) 2. \(-\frac{1}{2}xy^2\) (second term) 3. \(6x^2y^2\) (third term) ### Step 3: Conclusion on the number of terms From the above identification, we see that there are a total of 3 terms in the expression. ### Step 4: Classify the expression Since the expression contains 3 terms, we classify it as a trinomial. A polynomial with three terms is called a trinomial. ### Final Answer - The number of terms in the expression is **3**. - This expression is called a **trinomial**. ---
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