When a=3,b=0, c=-2 find the value of : ` a^(3)+b^(3)+c^(3)-3abc`

Answer

To solve the expression \( a^3 + b^3 + c^3 - 3abc \) given \( a = 3 \), \( b = 0 \), and \( c = -2 \), we can follow these steps:

### Step 1: Substitute the values of a, b, and c into the expression.
We start with the expression:
\[ a^3 + b^3 + c^3 - 3abc \]
Substituting the values:
\[ 3^3 + 0^3 + (-2)^3 - 3 \cdot 3 \cdot 0 \cdot (-2) \]

### Step 2: Calculate each term.
Now, we calculate each term separately:
- \( 3^3 = 27 \)
- \( 0^3 = 0 \)
- \( (-2)^3 = -8 \)
- \( 3 \cdot 3 \cdot 0 \cdot (-2) = 0 \) (since any number multiplied by 0 is 0)

### Step 3: Combine the results.
Now, we can combine the results:
\[ 27 + 0 - 8 - 0 \]
This simplifies to:
\[ 27 - 8 = 19 \]

### Final Answer:
Thus, the value of \( a^3 + b^3 + c^3 - 3abc \) is:
\[ \boxed{19} \]