Pinky runs around a rectangular park with length 80 m and breadth 55 m while Pankaj runs around a square park of side 75 m. Who covers more distance and by how much?

Answer

To solve the problem, we need to find the distance each person runs around their respective parks, which involves calculating the perimeter of the rectangular park for Pinky and the perimeter of the square park for Pankaj.

### Step-by-Step Solution:

1. **Calculate the Perimeter of the Rectangular Park (Pinky's Park)**:
- The formula for the perimeter (P) of a rectangle is given by:
\[ P = 2 \times (l + b) \]
- Where \( l \) is the length and \( b \) is the breadth.
- Here, \( l = 80 \, \text{m} \) and \( b = 55 \, \text{m} \).
- Plugging in the values:
\[ P = 2 \times (80 + 55) = 2 \times 135 = 270 \, \text{m} \]

2. **Calculate the Perimeter of the Square Park (Pankaj's Park)**:
- The formula for the perimeter (P) of a square is given by:
\[ P = 4 \times \text{side} \]
- Where the side length is \( 75 \, \text{m} \).
- Plugging in the value:
\[ P = 4 \times 75 = 300 \, \text{m} \]

3. **Compare the Distances Covered**:
- Pinky covers a distance of \( 270 \, \text{m} \).
- Pankaj covers a distance of \( 300 \, \text{m} \).
- To find out who covers more distance, we compare the two distances:
\[ 300 \, \text{m} > 270 \, \text{m} \]
- Therefore, Pankaj covers more distance than Pinky.

4. **Calculate the Difference in Distance**:
- To find out by how much Pankaj covers more distance than Pinky:
\[ \text{Difference} = 300 \, \text{m} - 270 \, \text{m} = 30 \, \text{m} \]

### Final Answer:
Pankaj covers more distance than Pinky by \( 30 \, \text{m} \).

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