A matchbox measures 4 cm by 2.5 cm by 15 cm. What will be the volume of a packet containing 12 such matchboxes?

Answer

To find the volume of a packet containing 12 matchboxes, we will follow these steps:

### Step 1: Identify the dimensions of the matchbox
The dimensions of the matchbox are:
- Length (l) = 4 cm
- Width (w) = 2.5 cm
- Height (h) = 15 cm

### Step 2: Calculate the volume of one matchbox
The formula for the volume (V) of a rectangular prism (or cuboid) is:
\[ V = l \times w \times h \]

Substituting the values:
\[ V = 4 \, \text{cm} \times 2.5 \, \text{cm} \times 15 \, \text{cm} \]

### Step 3: Perform the multiplication
First, multiply the length and width:
\[ 4 \times 2.5 = 10 \, \text{cm}^2 \]

Now, multiply this result by the height:
\[ 10 \, \text{cm}^2 \times 15 \, \text{cm} = 150 \, \text{cm}^3 \]

Thus, the volume of one matchbox is:
\[ V = 150 \, \text{cm}^3 \]

### Step 4: Calculate the volume of 12 matchboxes
To find the total volume of 12 matchboxes, we multiply the volume of one matchbox by 12:
\[ \text{Total Volume} = 12 \times 150 \, \text{cm}^3 \]

### Step 5: Perform the multiplication
Calculating this gives:
\[ 12 \times 150 = 1800 \, \text{cm}^3 \]

### Final Answer
The volume of a packet containing 12 matchboxes is:
\[ 1800 \, \text{cm}^3 \]

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