A block of mass 10kg is dragged across a horizontal surface by pulling the block with force of 100N. The force is applied by attaching a chord to the block. The chord is inclined at an angle of `60^(@)` with the horizontal. If the coefficient of kinetic friction is `0.2` what is the acceleration of the block ?

Explanation

To solve the problem, we will follow these steps:

### Step 1: Identify the forces acting on the block
- The weight of the block (W) = mg = 10 kg × 10 m/s² = 100 N (acting downwards).
- The pulling force (F) = 100 N at an angle of 60° with the horizontal.
- The normal force (N) acts upwards from the surface.
- The frictional force (f) acts opposite to the direction of motion.

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