The time taken for an ice block to slide down on inclined surface of inclination `60^(@)` is 1-2 times the time taken by the same ice block to slide down a frictionless inclined plane of the same inclination. Calculate the coefficient of friction between ice and the inclined plane ?

Explanation

To solve the problem of finding the coefficient of friction between the ice block and the inclined plane, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Information:**
- Inclination angle, \( \theta = 60^\circ \)
- The time taken for the ice block to slide down the inclined surface with friction is \( t = \frac{1}{2} T \) (where \( T \) is the time taken on a frictionless plane).

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