If the length of a second's pendulum is decreased by 2 %, find the gain or loss in time per day.

Explanation

`T=2pisqrt(l//g)`
For a seconds pendulum, T = 2s
`2=2pisqrt(l/g)" "...(i)`
The new length when it is decreased by 2% is `(lxx98)/100 =0.98l`
New tirne period = `t=2pisqrt((0.98l)/g)" "...(ii)`
Dividing equation (ii) by (i)
`t/2 =sqrt((0.98l)/g)xxsqrt(g/l)`
`t=sqrt(0.98)xx2 = 1.98s`