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A body executing shm completes 120 oscil...

A body executing shm completes 120 oscillations per minute. If the amplitude of oscillations is 6 cm, find the velocity and acceleration of the particle when it is at a distance of 4 cm from the mean position?

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The correct Answer is:
0.56 m/s, 6.31 `m//s^2`
`v=omegasqrt(a^2-y^2)=2pixx(120//60)sqrt(6^2-4^2)=0.56 m//s.alpha=omega^2y = (4pi^2) xx4 =63.1 ms^(-2)`
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