Home
Class 11
PHYSICS
In a shm, what is the minimum time requi...

In a shm, what is the minimum time required for a particle to move between two points 10 cm on either side of the mean position ? The amplitude and time period of the particle are 20 cm and 2 seconds respectively.

Text Solution

Verified by Experts

The correct Answer is:
0.34 s

`y = a sin(2pi//T) , 10 = 20 sin (2pi//2) t , t = 0.17 s , "Time " = 0.34 s`
Promotional Banner

Topper's Solved these Questions

  • OSCILLATIONS

    ICSE|Exercise SELECTED PROBLEMS (FROM ENERGY OF AS.H. OSCILLATOR )|9 Videos
  • OSCILLATIONS

    ICSE|Exercise SELECTED PROBLEMS (FROM TIME PERIOD OF OSCILLATION OF A S.H. OSCILLATOR)|19 Videos
  • OSCILLATIONS

    ICSE|Exercise VERY SHORT ANSWER QUESTIONS |13 Videos
  • MOTION IN FLUIDS

    ICSE|Exercise SELECTED PROBLEMS (FROM POISEUILLE.S FORMULA) |19 Videos
  • PROPERTIES OF MATTER

    ICSE|Exercise MODULE 4 ( TEMPERATURE ) UNSOLVED PROBLEMS|12 Videos

Similar Questions

Explore conceptually related problems

A particle executes SHM with amplitude of 20 cm and time period of 12 s. What is the minimum time required for it to move between two points 10 cm on either side of the mean position?

Time period of a particle executing SHM is 8 sec. At t=0 it is at the mean position. The ratio of the distance covered by the particle in the 1st second to the 2nd second is:

The kinetic energy of a particle, executing S.H.M. is 16 J when it is in its mean position. IF the amplitude of oscillation is 25 cm and the mass of the particle is 5.12 Kg, the time period of its oscillations is

A particle executes shm in a line 10 cm long. When it passes through the mean position its velocity is 15 cms^(-1) . Find the period.

Acceleration of a particle in SHM at displacement x=10 cm (from the mean position is a =-2.5 cm//s^(2) ). Find time period of oscillations.

A particle performing SHM with amplitude 10cm . At What distance from mean position the kinetic energy of the particle is thrice of its potential energy ?

The amplitude of a particle executing SHM about O is 10 cm . Then

A particle moves in a circle of radius 5 cm with constant speed and time period 0.2pis . The acceleration of the particle is

The time period of a particle executing SHM is T . After a time T//6 after it passes its mean position, then at t = 0 its :

A particle executes shm with an amplitude of 10 cm and a period of 5 s. Find the velocity and acceleration of the particle of a distance 5 cm from the equilibrium position.