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A cell utilises the following reaction: ...

A cell utilises the following reaction:
`2CO^(3+) (aq)+Zn(s) to 2CO^(2+)(aq)+Zn^(2+) (aq)`
What is the effect on cell emf of each of the following changes?
The size or area of Zn (s) electrode is doubled

Text Solution

Verified by Experts

The emf is an intensive property and so the size of the electrode shall not affect the emf of the cell.
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BODY BOOKS PUBLICATION-ELECTROMOTIVE FORCE -EXERCISE
  1. A cell utilises the following reaction: 2CO^(3+) (aq)+Zn(s) to 2CO^(...

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  2. Is 1M H^+ solution under hydrogen gas at 1 atm capable of oxidising Ag...

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  3. The potential of hydrogen electrode is -118mV. The concentration of H^...

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  4. E^@ for the half cell Zn^(2+)|Zn is -0.76V emf of the cell Zn|Zn^(2+...

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  5. The standard reduction potentials at 298K for the following half react...

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  6. The standard reduction potentials E^@ for the half reactions are as ...

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  7. From the following E^@ values of half cells, (i) A+e to A^(-) , E^@=...

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  8. From the following E^@ values of half cells (i) A to A^(+)+e, E^@=+1...

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  9. From the following E^@ values of half cells (i) A^(3-)to A^(2-) +e,...

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  10. IF the following half cells have the E^@ values as Fe^(3+)+e to Fe^(...

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  11. E^@ (red.) values of the half cells Mg^(2+)//Mg and Cl2//Cl^- are resp...

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  12. For the cell reaction Zn(s)+Mg^(2+) (1M)=Zn^(2+) (1M) +Mg, the emf has...

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  13. E^@ for F2+2e=2F^(-) is 2.8V, E^@ for 1/2 F2+e=F^(-) is

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  14. Delta G^@ of the cell reaction AgCl(s)+1/2H2(g)=Ag(s)+H^+ +Cl^(-) is ...

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  15. The value of equilibrium constant for the feasible cell reaction is

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  16. E^@ for the reaction Fe+Zn^(2+)=Zn+Fe^(2+) is -0.35 V. The given cell...

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  17. A galvanic cell is composed of two hydrogen electrodes, one of which i...

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  18. 1/2 H2(g)+AgCl(s)=H^+ (aq)+Cl^(-) (aq)+Ag(s) occurs in the galvanic c...

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  19. For the cell Tl|Tl^(+) (0.001M) ||Cu^(2+) (0.1M) |Cu. E(cell) at 25^@C...

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  20. (i) E^@ (Cu^(2+),Cu)=0.34V (ii) E^@(Cu^+,Cu)=+0.52V (iii) E^@[O2(...

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  21. Given below the half cell reactions Mn^(2+)+2e to Mn, E^@=-1.18V 2...

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