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A Cu rod is dipped in 0.1M CuSO4 solutio...

A Cu rod is dipped in 0.1M `CuSO_4` solution. Calculate the potential of this half cell if `CuSO_4` undergoes 90% dissociation at this dilution at `25^@C. E_(Cu,Cu^(2+))^@=-0.34V`

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0.31V
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BODY BOOKS PUBLICATION-ELECTROMOTIVE FORCE -PROBLEMS
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