Home
Class 12
CHEMISTRY
The standard potentials, E^@ for the hal...

The standard potentials, `E^@` for the half reaction are as
`Zn=Zn^(2+)+2e^(-) , E^@=0.76V`
`Fe=Fe^(2+)+2e^(-) , E^@=0.41V`
The emf for the cell reaction `Fe^(3+) +Zn to Zn^(2+)+Fe` is

A

`-0.35V`

B

`+0.35V`

C

`+1.17V`

D

`-1.17V`

Text Solution

Verified by Experts

B
Promotional Banner

Topper's Solved these Questions

  • ELECTROMOTIVE FORCE

    BODY BOOKS PUBLICATION|Exercise EXERCISE |25 Videos

  • ELECTROMOTIVE FORCE

    BODY BOOKS PUBLICATION|Exercise EXERCISE |25 Videos

  • ELECTROCHEMISTRY

    BODY BOOKS PUBLICATION|Exercise EXAMPLES|134 Videos

  • General Principles and Processes of Isolation of Elements

    BODY BOOKS PUBLICATION|Exercise Example|108 Videos

Similar Questions

Explore conceptually related problems

The standard reduction potentials E^@ for the half reactions are as Zn=Zn^(2+)+2e, E^@=+0.76V Fe=Fe^(2+)+2e, E^@=+0.41V the emf of the cell reaction, Fe^(2+)+Zn=Zn^(2+)+Fe is

The standard E.M.F. for the cell reaction: Zn(s) + Cu^(2+) (aq) - Zn^(2+) (aq) + (Cu) is 1.10 volts at 25^(@) C. The EMF. For the cell reaction when 0.01 M Cu^(2+) and 0.1 M Zn^(2+) solutions are used at 25^(@) C is:

IF the following half cells have the E^@ values as Fe^(3+)+e to Fe^(2+), E^@=0.77Vand Fe^(2+)+2e to Fe, E^@=-0.44V the E^@ of the cell half cell Fe^(3+)+3e to Fe will be

E^@ for the reaction Fe+Zn^(2+)=Zn+Fe^(2+) is -0.35 V. The given cell reaction is

Given below the half cell reactions Mn^(2+)+2e to Mn, E^@=-1.18V 2(Mn^(3+)+e to Mn^(2+)), E^@=+1.51 V The E^@ for , 3Mn^(2+) to Mn + 2Mn^(3+) will be

The standard reduction potentials at 298K for the following half reactions are given against each. Zn^(2+) (aq)+2e= Zn(s), -0.762V Cr^(3+) (aq) +3e= Cr(s), -0.74V 2H^+ +2e=H_2 (g), pm 0.0V Fe^(3+) (aq)+e =Fe^(2+) (aq), +0.77V What is the strongest reducing agent?

E^@ for the half cell Zn^(2+)|Zn is -0.76V emf of the cell Zn|Zn^(2+) (1M) |2H^+ (1M) |H_2 (1atm) is

The measured EMF at 298 K for the cell reaction, Zn(s) + Cu^(2+)(1.0 M) rarr Cu(s) + Zn^(2+)(0.1M) is 1.13 V. Calculate E^(@) for the cell reaction.

Given E_((Cr^(3+)) / (Cr)=-0.72 V . E_(Fe^(2+)//Fe)^(@)=-0.42 V The potential for the cell, Cr∣Cr^(3+) (0.1M)∣∣Fe ^(2+) (0.01M)∣Fe is:

BODY BOOKS PUBLICATION-ELECTROMOTIVE FORCE -PROBLEMS
  1. Copper can reduce zinc ions if the resultant copper ions can be kept a...

    Text Solution

    |

  2. A cell contains two hydrogen electrodes. The negative electrode is in ...

    Text Solution

    |

  3. The standard potentials, E^@ for the half reaction are as Zn=Zn^(2+)...

    Text Solution

    |

  4. Given that Fe^(3+)+e leftrightarrow Fe^(2+), E^@=0.77V Fe^(2+)+2e ...

    Text Solution

    |

  5. From the following values of E^@ drawn from the emf series, calculate ...

    Text Solution

    |

  6. Will Fe (s) be oxidised to Fe^(2+) by reacting with 1M HCl? E(Fe,Fe^...

    Text Solution

    |

  7. A galvanic cell is composed of a standard Zn electrode and a chromium ...

    Text Solution

    |

  8. The standard electrode potential corresponding to the reduction Cr^(3+...

    Text Solution

    |

  9. The emf of a cell consisting of a copper and a lead electrode immersed...

    Text Solution

    |

  10. What is the potential of a hydrogen electrode at pH=10?

    Text Solution

    |

  11. We have an oxidation -reduction system: [Fe(CN)6]^(3-) +e leftrighta...

    Text Solution

    |

  12. Calculate the emf of the following cell at 25^@C Fe|FeSO4||CuSO4|Cu ...

    Text Solution

    |

  13. Calculate the emf of the following cells, find their cells reactions u...

    Text Solution

    |

  14. Calculate the emf of the following cells, find their cells reactions u...

    Text Solution

    |

  15. Calculate the emf of the following cells, find their cells reactions u...

    Text Solution

    |

  16. Neglecting the liquid junction potential, calculate the emf of the fol...

    Text Solution

    |

  17. The emf of the cell, (Pt) H2|H^+ (c=unknown) ||KCN soln. |HgCl2|Hg i...

    Text Solution

    |

  18. Calculate the cell potential for the following galvanic cell: The f...

    Text Solution

    |

  19. Find the equilibrium constant at 25^@C for the reaction, Hg2(NO3)2+2...

    Text Solution

    |

  20. Calculate the potential of a silver electrode in a saturated solution ...

    Text Solution

    |