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From the following values of E^@ drawn f...

From the following values of `E^@` drawn from the emf series, calculate standard emf and the equilibrium constant for the reaction
`Hg^(2+)+Hg leftrightarrow Hg_2^(2+)`
`E_(Hg_2^(2+),Hg)^@=0.788V, E_(Hg^(2+),Hg_2^(2+))^@=0.92V`

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`0.132 V, 1.72 times 10^2`
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