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Neglecting the liquid junction potential...

Neglecting the liquid junction potential, calculate the emf of the following cell at `25^@C`
`H_2 (1atm) |0.5 M HCOOH||1M CH_3 COOH|H_2(1atm)`
The dissociation constants of HCOOH and `CH_3COOH` are `1.77 times 10^-4` and `1.8 times 10^-8` respectively.

Text Solution

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`-0.0246` volt
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