When photons of energy 4.25eV strike the surface of a metal A, the ejected photoelectrons have maximum kinetic energy, `T_A` (expressed in eV) and deBroglie wavelength `lambda_A`. The maximum kinetic energy of photoelectrons liberated from another metal B by photons of energy 4.20V is `T_B = T_A -1.50eV`. If the deBroglie wavelength of those photoelectrons is `lambda_B = 2lambda_A` then

When photons of energy 4.25 eV strike the surface of a metal A, the ejected photoelectrons have maximum kinetic energy, T_(A) (expressed in eV) and de Broglie wavelength lambda_(A) . The mximum kinetic energy of photoelectrons liberated from another metal B by photons of energy 4.20 eV is T_(B) = T_(A) - 1.50 eV . If the de Broglie wavelength of these photoelectrons is lambda_(B) = 2 lambda_(A) , then which is not correct :

When photons of energy 4.25 eV strike the surface of metal A, the ejected photoelectrons have maximum kinetic energy T_(A) eV and De-broglie wavelength lambda_(A) . The maximum energy of photoelectron liberated from another metal B by photon of energy 4.70 eV is T_(B) = (T_(A) - 1.50) eV if the de Brogle wavelength of these photoelectrons is lambda_(B) = 2 lambda_(A) , then

When photons of energy 4.25 eV strike the surface of metal A, the ejected photoelectrons have maximum kinetic energy T_(A) eV and De-broglie wavelength lambda_(A) . The maximum energy of photoelectron liberated from another metal B by photon of energy 4.70 eV is T_(B) = (T_(A) - 1.50) eV if the de Brogle wavelength of these photoelectrons is lambda_(B) = 2 lambda_(A) , then