A body of mass `3 kg` is under a constant force which causes a displacement `s` metre in it, given by the relation `s=(1)/(3)t^(2)`, where `t` is in seconds. Work done by the force in 2 seconds is

A body of mass 6kg is under a force which causes displacement in it given by S= (t^(2))/(4) maters where t is time . The work done by the force in 2 sec is

A body of mass 3 kg is under a force , which causes a displacement in it is given by S = (t^(3))/(3) (in metres). Find the work done by the force in first 2 seconds.

A body of mass 5 kg at rest under the action of a force which gives its velocity given by v = 3 xx t m//s , here 't' is time in seconds. The work done by the force in two seconds will be

The displacement of a partcle is given by x=(t-2)^(2) where x is in metre and t in second. The distance coverred by the particle in first 3 seconds is

The displacement x of a particle of mass m kg moving in one dimension, under the action of a force, is related to the time t by the equation t=4x+3 where x is in meters and t is in seconds. The work done by the force in the first six seconds in joules is