Find the foot of the perpendicular from `(1,2)` to the line `x-3y+4=0`

The foot of the perpendicular from (1,2) on the line x-3y+7=0 is

(a) Find the length and the foot of the perpendicular from : P (1,1,2) to the plane 2x - 2y + 4z + 5 = 0 (b) Find the co-ordinates of the foot of the perpendicular drawn from the origin to the plane 2x - 3y + 4z - 6 = 0.

The foot of the perpendicular from (2,-5) on the line 3x-4y+10=0 is

Find the foot of perpendicular from (0, 2, 3) to the line (x-3)/2= (y-1)/2=(z+4)/3 .

The coordinates of the foot of the perpendicular from (2,3) to the line 3x+4y - 6 = 0 are

Find the foot of the perpendicular from the point (0,2,3) on the line (x+3)/(5)=(y-1)/(2)=(z+4)/(3) . Also,find the length of the perpendicular.

Find the foot of the perpendicular from 1,2,-3 ) to th lin(x+1)/(2)=(y-3)/(-2)=(z-3)/(-1)

Find the foot of the perpendicular from the point (2,3,-8) to the line (4-x)/(2)=(y)/(6)=(1-z)/(3). Find the perpendicular distance from the given point to the line.

Find the coordinates of the foot of perpendicular from a point (-1, 3) to the line 3x-4y-16=0