A copper wire of cross-section A is under a tension T .Its Young's modulus is Y and Poisson's ratio sigma .The decrease in cross-section of wire will be

A copper wire of cross sectional asrea 0.01 cm is under a tension of 20 N. Find the decrease in the cross sectional area. Young modulus of copper =1.1xx10^11Nm^-2 and Poisson ratio 0.32.

A force F doubles the length of wire of cross-section a The Young modulus of wire is

A metal wire of length L, area of cross-section A and Young's modulus Y behaves as a spring of spring constant k.

A wire of length L and cross-sectional area A is made of material of Young's modulus Y. The work done in stretching the wire by an amount x is

wire of length I has a ear mass density lambda and area of cross-section A and the Young's modulus y is suspended vertically from rigid support. The extension produced in wire due to its own weight

An iron wire an copper wire having same length and cross-section are suspended form same roof Young's modulus of copper is 1//3rd that of iron. Then the ratio of the weighs to be added at their ends so that their ends are at the same level is

A wire of length L and radius r is loaded with a weigth Mg. If y and sigma denote the Youngs modulus and Poisson's ratio of the material of the wire respectively. Then the decreases in the radius of the wire is given by

Consider the situation shown in figure. The force F is equal to mg. If area of cross-section of the string is A and its Young's modulus is Y, the strain developed in the wire is (the string is light and there is no friction anywhere)