Home
Class 14
MATHS
From a point on a circular track 5 km lo...

From a point on a circular track 5 km long A, B and C started running in the same direction at the same time with speed of `2 1/2` km per hour 3 km per hour and 2 km per hour respectively. Then on the starting point all three will meet again after.

A

30 hours

B

6 hours

C

10 hours

D

15 hours

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to calculate the time taken by each runner to complete one lap around the circular track and then find the least common multiple (LCM) of those times. ### Step 1: Calculate the time taken by A to complete the track - **Speed of A** = \(2 \frac{1}{2}\) km/h = \( \frac{5}{2} \) km/h - **Circumference of the track** = 5 km - **Time taken by A** = \( \frac{\text{Circumference}}{\text{Speed}} = \frac{5 \text{ km}}{\frac{5}{2} \text{ km/h}} = 2 \text{ hours} \) **Hint:** To find the time taken to complete a circular track, divide the length of the track by the speed of the runner. ### Step 2: Calculate the time taken by B to complete the track - **Speed of B** = 3 km/h - **Time taken by B** = \( \frac{5 \text{ km}}{3 \text{ km/h}} = \frac{5}{3} \text{ hours} \) **Hint:** Use the same formula: Time = Distance / Speed for each runner. ### Step 3: Calculate the time taken by C to complete the track - **Speed of C** = 2 km/h - **Time taken by C** = \( \frac{5 \text{ km}}{2 \text{ km/h}} = \frac{5}{2} \text{ hours} \) **Hint:** Remember to convert the speeds into a consistent unit (km/h) before calculating the time. ### Step 4: Find the LCM of the times taken by A, B, and C - Times: - A: 2 hours = \( \frac{2}{1} \) - B: \( \frac{5}{3} \) hours - C: \( \frac{5}{2} \) hours To find the LCM of these fractions, we can convert them to a common denominator: - The LCM of the numerators (2, 5, 5) is 10. - The GCD of the denominators (1, 3, 2) is 1. Thus, the LCM of the times is: \[ \text{LCM} = \frac{\text{LCM of numerators}}{\text{GCD of denominators}} = \frac{10}{1} = 10 \text{ hours} \] **Hint:** To find the LCM of fractions, find the LCM of the numerators and the GCD of the denominators. ### Conclusion A, B, and C will meet again at the starting point after **10 hours**. **Final Answer:** 10 hours
Promotional Banner

Topper's Solved these Questions

  • GEOMETRY TRIANGLES

    ADVANCED MATHS BY ABHINAY MATHS ENGLISH|Exercise QUESTIONS |132 Videos
  • MAINS MOCK TEST

    ADVANCED MATHS BY ABHINAY MATHS ENGLISH|Exercise QUESTION|97 Videos

Similar Questions

Explore conceptually related problems

A speed of 45 km per hour is the same as

Two trains are running on parallel lines in the same direction at a speed of 50 km. and 30 km per hour respectively. The faster train crosses a man in slower train in 18 seconds. The length of the faster train is:

ADVANCED MATHS BY ABHINAY MATHS ENGLISH-LCM & HCF -MULTIPLE CHOICE QUESTIONS
  1. Which is the least number which when doubled will be exactly divisible...

    Text Solution

    |

  2. The smallest square number divisible by 10, 16 and 24 is:

    Text Solution

    |

  3. From a point on a circular track 5 km long A, B and C started running ...

    Text Solution

    |

  4. What is the least number of square tiles required to pave the floor of...

    Text Solution

    |

  5. If the ratio of the two numbers is 2 : 3 and their LCM is 54, then the...

    Text Solution

    |

  6. The ratio of two numbers is 4 : 5 and their LCM is 120. The numbers ar...

    Text Solution

    |

  7. Three numbers which are co-prime to each other are such that the pr...

    Text Solution

    |

  8. HCF and LCM of two numbers are 7 and 140 respectively. If the numbers ...

    Text Solution

    |

  9. The HCF of two numbers is 15 and their LCM is 300. If one of the numbe...

    Text Solution

    |

  10. The H.C.F. of two numbers is 23 and the other two factors of their ...

    Text Solution

    |

  11. If the students of a class can be grouped exactly into 6 or 8 or 10, t...

    Text Solution

    |

  12. The least number which when divided by 4, 6, 8 and 9 leave zero remain...

    Text Solution

    |

  13. The number nearest to 10000, which is exactly divisible by each of 3, ...

    Text Solution

    |

  14. Let N be the greatest number that will divide 1305 , 4665 and 6905 Iea...

    Text Solution

    |

  15. The sum of two numbers is 36 and their HCF is 4. How many pairs of suc...

    Text Solution

    |

  16. Find the greatest number that divides 80 and 115 leaving remainder 8 a...

    Text Solution

    |

  17. The H.C.F. and L.C.M. of two 2 digit numbers are 16 and 480 re- specti...

    Text Solution

    |

  18. The smallest number, which divided by 12 and 16 leaves remainder 5 and...

    Text Solution

    |

  19. A number which when divided by 10 leaves a remainder of 9, when divi...

    Text Solution

    |

  20. What is the smallest number which leaves remainder 3 when divided by a...

    Text Solution

    |