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If P=2^(3).3^(10).5: Q = 2^(5).3.7, then...

If `P=2^(3).3^(10).5: Q = 2^(5).3.7`, then HCF of P and Q is:

A

`2.3.5.7`

B

`3.2^(3)`

C

`2^(2)3^(7)`

D

`2^(5).3^(10).5.7`

Text Solution

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The correct Answer is:
To find the HCF (Highest Common Factor) of the numbers \( P \) and \( Q \), we start by expressing both numbers in their prime factorization form. ### Step 1: Write down the prime factorization of \( P \) and \( Q \) Given: - \( P = 2^3 \times 3^{10} \times 5^1 \) - \( Q = 2^5 \times 3^1 \times 7^1 \) ### Step 2: Identify the common prime factors Next, we identify the common prime factors between \( P \) and \( Q \): - The common prime factors are \( 2 \) and \( 3 \). - The prime factor \( 5 \) in \( P \) and \( 7 \) in \( Q \) are not common. ### Step 3: Determine the minimum power of each common prime factor Now, we take the minimum power for each of the common prime factors: - For \( 2 \): The powers are \( 3 \) (from \( P \)) and \( 5 \) (from \( Q \)). The minimum is \( \min(3, 5) = 3 \). - For \( 3 \): The powers are \( 10 \) (from \( P \)) and \( 1 \) (from \( Q \)). The minimum is \( \min(10, 1) = 1 \). ### Step 4: Write down the HCF using the minimum powers Now we can write the HCF using the minimum powers we found: \[ \text{HCF}(P, Q) = 2^{\min(3, 5)} \times 3^{\min(10, 1)} = 2^3 \times 3^1 \] ### Step 5: Calculate the HCF Finally, we can compute the HCF: \[ \text{HCF}(P, Q) = 2^3 \times 3^1 = 8 \times 3 = 24 \] Thus, the HCF of \( P \) and \( Q \) is \( 24 \).
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ADVANCED MATHS BY ABHINAY MATHS ENGLISH-LCM & HCF -MULTIPLE CHOICE QUESTIONS
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