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Two bombs blast at an interval of 10 min...

Two bombs blast at an interval of 10 minutes. A person running away from that place hears the two blasts at an interval of 12 minutes. If speed of sound is 330 m/s find the speed of the person and the distance he covered by running away from the blast.

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The correct Answer is:
To solve the problem step by step, we will follow these steps: ### Step 1: Understand the Time Difference The two bombs explode at an interval of 10 minutes. However, the person running away hears the blasts at an interval of 12 minutes. **Hint:** Calculate the difference in time between the two intervals. ### Step 2: Calculate the Time Difference The time difference is: \[ 12 \text{ minutes} - 10 \text{ minutes} = 2 \text{ minutes} \] **Hint:** Convert the time difference from minutes to seconds. ### Step 3: Convert Minutes to Seconds To convert 2 minutes into seconds: \[ 2 \text{ minutes} \times 60 \text{ seconds/minute} = 120 \text{ seconds} \] **Hint:** Use the formula for distance traveled to find the distance the sound traveled in this time. ### Step 4: Calculate the Distance the Sound Traveled The speed of sound is given as 330 m/s. The distance traveled by sound in 120 seconds is calculated using the formula: \[ \text{Distance} = \text{Speed} \times \text{Time} \] \[ \text{Distance} = 330 \text{ m/s} \times 120 \text{ seconds} = 39600 \text{ meters} \] **Hint:** Now, we need to find the speed of the person running away from the blasts. ### Step 5: Calculate the Speed of the Person The person hears the two blasts at an interval of 12 minutes, which is 720 seconds. The distance covered by the person is the same as the distance traveled by sound (39600 meters). Using the formula for speed: \[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} \] \[ \text{Speed} = \frac{39600 \text{ meters}}{720 \text{ seconds}} \] **Hint:** Simplify the fraction to find the speed. ### Step 6: Simplify the Speed Calculation Calculating the speed: \[ \text{Speed} = \frac{39600}{720} = 55 \text{ m/s} \] ### Final Answer The speed of the person running away from the blast is **55 m/s**. ### Step 7: Calculate the Distance Covered by the Person To find the distance covered by the person during the 12 minutes (720 seconds): \[ \text{Distance} = \text{Speed} \times \text{Time} \] \[ \text{Distance} = 55 \text{ m/s} \times 720 \text{ seconds} = 39600 \text{ meters} \] ### Conclusion The speed of the person is **55 m/s**, and the distance covered by the person is **39600 meters**.
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ADVANCED MATHS BY ABHINAY MATHS ENGLISH-TIME, SPEED & DISTNACE -QUESTIONS
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  2. Metro leaves after every 10 minutes. A person starts running towards m...

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  3. Two bombs blast at an interval of 10 minutes. A person running away fr...

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  4. A person covers a distance of 80 km in 8 hours. some part of this jour...

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  8. A person has to cover 360 km distance. If he increases his speed by 10...

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  10. A train has been stopped for 6 minutes. Next stations is 36 kms away a...

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  13. A officer goes to office from his home, which is 8 km apart. His speed...

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  14. Speed of a man is 90 km/h after every 24 minutes he reduces his speed ...

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  15. Speed of a faster train is 100 km/hr and it takes 3 minutes rest after...

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  16. A bus meets an auto at 10:00 am while going on the same way towards ...

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  17. The metro service has a train going from A to B and B to A every hour,...

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  18. A father picks his child at 3:30 pm from school. One day the child lef...

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  19. Radha and Shyam start travelling from Delhi to Goa at the speed of 15 ...

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  20. Distance between A & B is 550 km. Both start walking towards each othe...

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