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A sum of money doubles itself at compoun...

A sum of money doubles itself at compound interest in 4 years. In how many years will it become 8 times?

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To solve the problem step by step, we will follow the logic used in the video transcript. ### Step 1: Understand the Problem We know that a sum of money doubles itself in 4 years at compound interest. We need to find out how many years it will take for the same sum to become 8 times. ### Step 2: Set Up the Initial Equation Let the principal amount be \( P \) and the rate of interest be \( R \). According to the formula for compound interest, the amount \( A \) after time \( T \) is given by: \[ A = P \left(1 + \frac{R}{100}\right)^T \] Since the amount doubles in 4 years, we can write: \[ 2P = P \left(1 + \frac{R}{100}\right)^4 \] ### Step 3: Simplify the Equation We can cancel \( P \) from both sides (assuming \( P \neq 0 \)): \[ 2 = \left(1 + \frac{R}{100}\right)^4 \] ### Step 4: Solve for \( R \) Taking the fourth root of both sides, we get: \[ 1 + \frac{R}{100} = 2^{1/4} \] Calculating \( 2^{1/4} \): \[ 2^{1/4} = \sqrt[4]{2} \approx 1.189207 \] Now, we can express \( R \): \[ \frac{R}{100} = 2^{1/4} - 1 \approx 1.189207 - 1 = 0.189207 \] Thus, \[ R \approx 0.189207 \times 100 \approx 18.92 \] ### Step 5: Set Up the Second Equation for 8 Times Now we need to find out how long it takes for the amount to become 8 times the principal: \[ 8P = P \left(1 + \frac{R}{100}\right)^T \] Again, we can cancel \( P \): \[ 8 = \left(1 + \frac{R}{100}\right)^T \] ### Step 6: Substitute the Value of \( 1 + \frac{R}{100} \) From our earlier calculation, we know: \[ 1 + \frac{R}{100} = 2^{1/4} \] Thus, we can rewrite the equation as: \[ 8 = \left(2^{1/4}\right)^T \] ### Step 7: Rewrite 8 in Terms of Powers of 2 We know that \( 8 = 2^3 \). Therefore, we can write: \[ 2^3 = \left(2^{1/4}\right)^T \] ### Step 8: Equate the Exponents Since the bases are the same, we can equate the exponents: \[ 3 = \frac{T}{4} \] ### Step 9: Solve for \( T \) Multiplying both sides by 4 gives: \[ T = 3 \times 4 = 12 \] ### Conclusion Thus, it will take **12 years** for the sum to become 8 times. ---
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ADVANCED MATHS BY ABHINAY MATHS ENGLISH-COMPOUND INTEREST -QUESTIONS
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