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A sum of money becomes 3 times of itself...

A sum of money becomes 3 times of itself in 6 years at compound interest. In how many years will it become 81 times?

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To solve the problem, we need to determine how many years it will take for a sum of money to become 81 times its original amount at compound interest, given that it becomes 3 times its original amount in 6 years. ### Step-by-Step Solution: 1. **Understanding the Problem**: We know that a sum of money becomes 3 times itself in 6 years. This means if the principal amount is \( P \), then after 6 years, the amount \( A \) is: \[ A = 3P \] 2. **Using the Compound Interest Formula**: The formula for compound interest is: \[ A = P(1 + r)^t \] where \( A \) is the amount after time \( t \), \( P \) is the principal, \( r \) is the rate of interest, and \( t \) is the time in years. 3. **Setting Up the Equation**: From the information given, we can set up the equation for the first scenario (6 years): \[ 3P = P(1 + r)^6 \] Dividing both sides by \( P \) (assuming \( P \neq 0 \)): \[ 3 = (1 + r)^6 \] 4. **Finding the Rate of Interest**: To find \( r \), we take the sixth root of both sides: \[ 1 + r = 3^{1/6} \] Therefore, \[ r = 3^{1/6} - 1 \] 5. **Finding the Time for 81 Times**: Now, we want to find out how long it will take for the sum to become 81 times itself. So we set up the equation for this scenario: \[ 81P = P(1 + r)^t \] Dividing both sides by \( P \): \[ 81 = (1 + r)^t \] 6. **Relating 81 to 3**: Notice that \( 81 = 3^4 \). Therefore, we can rewrite the equation as: \[ 3^4 = (1 + r)^t \] 7. **Using the Previous Equation**: Since we know from step 4 that \( (1 + r)^6 = 3 \), we can express \( (1 + r)^t \) in terms of \( (1 + r)^6 \): \[ (1 + r)^t = (1 + r)^{6 \cdot \frac{t}{6}} = (3)^{\frac{t}{6}} \] 8. **Setting the Exponents Equal**: Now we have: \[ (3)^{\frac{t}{6}} = 3^4 \] Since the bases are the same, we can set the exponents equal to each other: \[ \frac{t}{6} = 4 \] 9. **Solving for \( t \)**: Multiplying both sides by 6 gives: \[ t = 24 \] ### Final Answer: It will take **24 years** for the sum of money to become 81 times its original amount at compound interest.
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  9. Compound Interest on a sum of money is Rs. 350 in 4 years at 33(1)/(3...

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  14. The difference of S.I. and C.I on a sum at 10% per annum for 3 years i...

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  15. The difference of SI and CI on a sum at 5% per annum for 3 years is Rs...

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  16. The difference of S.I and C.I on a sum at 5% per annum for 3 years is ...

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  17. The difference of C.I and S.I on a sum at 5% per annum for 3 years is ...

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  18. The difference of S.I and C.I on a sum at 10% for 1(1)/(2) years is ...

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  19. The ratio of difference of S.I and C.I for 2 years and 3 years is (8)/...

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