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A sum of money becomes 8 times of itself...

A sum of money becomes 8 times of itself in 12 years at C.I. In how many years it will become 16 times of itself.

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To solve the problem step by step, we will follow the principles of compound interest. ### Step 1: Understand the Problem We need to find out how many years it takes for a sum of money to become 16 times itself, given that it becomes 8 times itself in 12 years. ### Step 2: Set Up the Known Information Let: - Principal amount = \( P \) - Rate of interest = \( R \) - Time for 8 times = 12 years - Amount after 12 years = \( 8P \) ### Step 3: Use the Compound Interest Formula The formula for compound interest is: \[ A = P \left(1 + \frac{R}{100}\right)^T \] Where: - \( A \) is the amount after time \( T \) - \( P \) is the principal - \( R \) is the rate of interest - \( T \) is the time in years For our case, we can write: \[ 8P = P \left(1 + \frac{R}{100}\right)^{12} \] ### Step 4: Simplify the Equation Dividing both sides by \( P \) (assuming \( P \neq 0 \)): \[ 8 = \left(1 + \frac{R}{100}\right)^{12} \] ### Step 5: Express 8 as a Power of 2 We know that: \[ 8 = 2^3 \] Thus, we can rewrite the equation as: \[ 2^3 = \left(1 + \frac{R}{100}\right)^{12} \] ### Step 6: Take the Cube Root To simplify, we take the cube root of both sides: \[ 2 = \left(1 + \frac{R}{100}\right)^{4} \] ### Step 7: Rewrite the Equation Now we can express \( 1 + \frac{R}{100} \): \[ 1 + \frac{R}{100} = 2^{\frac{1}{4}} = \sqrt[4]{2} \] ### Step 8: Find the Time for 16 Times Now we need to find \( T \) when the amount becomes \( 16P \): \[ 16P = P \left(1 + \frac{R}{100}\right)^T \] Dividing both sides by \( P \): \[ 16 = \left(1 + \frac{R}{100}\right)^T \] Since \( 16 = 2^4 \), we can write: \[ 2^4 = \left(1 + \frac{R}{100}\right)^T \] ### Step 9: Substitute the Value of \( 1 + \frac{R}{100} \) From Step 7, we know: \[ 1 + \frac{R}{100} = 2^{\frac{1}{4}} \] Substituting this into the equation: \[ 2^4 = \left(2^{\frac{1}{4}}\right)^T \] ### Step 10: Equate the Exponents This gives us: \[ 4 = \frac{T}{4} \] Multiplying both sides by 4: \[ T = 16 \] ### Conclusion Thus, it will take **16 years** for the sum of money to become 16 times itself. ---
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ADVANCED MATHS BY ABHINAY MATHS ENGLISH-COMPOUND INTEREST -QUESTIONS
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  14. The difference of S.I and C.I on a sum at 5% per annum for 3 years is ...

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  15. The difference of C.I and S.I on a sum at 5% per annum for 3 years is ...

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  16. The difference of S.I and C.I on a sum at 10% for 1(1)/(2) years is ...

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