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A sum of money becomes 9 times in 1 year...

A sum of money becomes 9 times in 1 year if compounded half yearly. How much time it will take to become 125 times if compounded yearly.

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To solve the problem step by step, we will break it down into two parts: first, we will find the interest rate when the sum becomes 9 times in 1 year compounded half-yearly, and then we will determine how long it will take for the same sum to become 125 times when compounded yearly. ### Step 1: Understanding the first scenario We know that a sum of money becomes 9 times in 1 year when compounded half-yearly. Let: - \( P \) = initial amount - After 1 year, the amount becomes \( 9P \) - Compounded half-yearly means it is compounded 2 times a year, so \( N = 2 \) - Time \( T = 1 \) year ### Step 2: Setting up the compound interest formula The formula for compound interest is given by: \[ A = P \left(1 + \frac{R}{100N}\right)^{NT} \] Where: - \( A \) = final amount - \( R \) = rate of interest per annum - \( N \) = number of times interest is compounded per year - \( T \) = time in years In our case: \[ 9P = P \left(1 + \frac{R}{200}\right)^{2 \times 1} \] ### Step 3: Simplifying the equation Dividing both sides by \( P \): \[ 9 = \left(1 + \frac{R}{200}\right)^{2} \] ### Step 4: Taking the square root Taking the square root of both sides: \[ 3 = 1 + \frac{R}{200} \] ### Step 5: Solving for \( R \) Subtracting 1 from both sides: \[ 2 = \frac{R}{200} \] Multiplying both sides by 200: \[ R = 400\% \] ### Step 6: Moving to the second scenario Now, we need to find out how long it will take for the same sum to become 125 times when compounded yearly. Let: - New amount \( A = 125P \) - Compounded yearly means \( N = 1 \) ### Step 7: Setting up the new compound interest equation Using the compound interest formula again: \[ 125P = P \left(1 + \frac{400}{100}\right)^{1 \times T} \] ### Step 8: Simplifying the new equation Dividing both sides by \( P \): \[ 125 = \left(1 + 4\right)^{T} \] \[ 125 = 5^{T} \] ### Step 9: Solving for \( T \) We can express 125 as \( 5^3 \): \[ 5^3 = 5^{T} \] Since the bases are the same, we can equate the exponents: \[ T = 3 \] ### Final Answer It will take **3 years** for the sum to become 125 times when compounded yearly. ---
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