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A man borrows Rs. 3000 at 10% per annum ...

A man borrows Rs. 3000 at 10% per annum and promises to pay Rs. 1000 every year. If he wish to finish all his what amount he have to pay in third year

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To solve the problem step by step, we will calculate the amount due at the end of each year, taking into account the interest and the payments made. ### Step 1: Calculate the amount due after the first year The initial amount borrowed is Rs. 3000, and the interest rate is 10% per annum. 1. **Calculate interest for the first year:** \[ \text{Interest} = \text{Principal} \times \text{Rate} = 3000 \times \frac{10}{100} = 300 \] 2. **Total amount due after the first year:** \[ \text{Total Amount} = \text{Principal} + \text{Interest} = 3000 + 300 = 3300 \] 3. **Payment made at the end of the first year:** \[ \text{Payment} = 1000 \] 4. **Remaining amount after the first year:** \[ \text{Remaining Amount} = 3300 - 1000 = 2300 \] ### Step 2: Calculate the amount due after the second year Now, we will calculate the interest on the remaining amount of Rs. 2300. 1. **Calculate interest for the second year:** \[ \text{Interest} = 2300 \times \frac{10}{100} = 230 \] 2. **Total amount due after the second year:** \[ \text{Total Amount} = 2300 + 230 = 2530 \] 3. **Payment made at the end of the second year:** \[ \text{Payment} = 1000 \] 4. **Remaining amount after the second year:** \[ \text{Remaining Amount} = 2530 - 1000 = 1530 \] ### Step 3: Calculate the amount due after the third year Now we will calculate the interest on the remaining amount of Rs. 1530. 1. **Calculate interest for the third year:** \[ \text{Interest} = 1530 \times \frac{10}{100} = 153 \] 2. **Total amount due after the third year:** \[ \text{Total Amount} = 1530 + 153 = 1683 \] ### Step 4: Final payment in the third year To clear all dues, the man needs to pay the total amount due at the end of the third year. \[ \text{Final Payment} = 1683 \] ### Summary of the Solution The man has to pay Rs. 1683 in the third year to finish all his dues. ---
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