Certain mass of oxygen exerts a pressure of 'P' atm in a vessel of volume 'V' at `25^@C`. In the same vessel what be the pressure of gas at 25 K ?

Explanation

Gay = lussac.s law is given as ` (P_1)/(P_2) = (T_1)/(T_2)`
` {:(P_1 =P atm,T_1 = 298 K),( P_2 =? ,T_2 =25 K):}`
Pressure of the gas at 25K =
`P_2 = (P_1 T_2)/(T_1) = (P xx 25 )/( 298 ) = 0.084 P atm`