Certain amount of a gas at `25^@C` and 76cm Hg occupies volume of 12.0L. What will be the pressure at a height where temperature is `10^@C` and volume is 12.8L?

Explanation

Equation of state is given as ` (P_1V_1)/(T_1 ) = (P_2 V_2)/(T_2)`

The pressure at the given height =
` P_2 = (P_1 V_1)/( T_1)xx (T_2)/(P_2) =( 76 xx 12 xx 283 )/( 12.8 xx 298 ) = 67.66 cm Hg `