One litre of hydrogen effused in 8min through a 8 fine aperture. What is the time required for the same volume of ozone to effuse under similar conditions?

Explanation

The ratio of times taken for same volume of two gases, under similar conditions is given by Graham.s equation
`(t_2)/(t_1) = sqrt((M_2)/(M_1)) or t_2 = t_1 sqrt((M_2)/(M_1))`
Time required for ozone to effuse `= 8 xx sqrt(48//2) = 39.2` min.