A vessel contains 0.25 moles of Helium and 0.15 moles of neon at 298K and 2.4 atmosphere pressure. Calculate the partial pressure of each gas in the mixture.

Explanation

Total Pressure .P. = 2.4atm
No. of moles of He=0.25
No. of moles of Ne=0.15
Total moles of n = 0.25 +0.15 = 0.4
Partial pressure = Total pressure X Mole-fraction
` P_(He) = (n_(He))/*( n ) xx P ( 0.25 )/( 0.4 ) xx 2.4 = 1.5 atm`
`P_( Ne ) = (n_(Ne))/(n ) x P = ( 0.15 )/( 0.4 ) xx 2.4 = 0. atm`