What is the pressure exerted by `10^(23)` gas molecules, each molecule of mass `10^(-23)`g, present in a container of volume one L and RMS speed of `1000 m s^(-1)`?

Explanation

Kinetic gas equation `PV = 1.3 mnc^2`
Pressure of the gas (P)
` P= ( mnC^2)/( 3V) = ( 10^(-23) xx 10^(23) xx 10^(10))/( 3 xx 1000 ) = 3.33 xx 10^6 dy cm^(-2)`