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Which salts form pale blue precipitates....

Which salts form pale blue precipitates.

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When ammonium hydroxide is added to solution B, a pale blue precipitate is formed. This pale blue precipitate dissolves in excess ammonium hydroxide giving an inky blue solution. What is the cation (positive ion) present in solution B ? What is the probable colour of solution B.

Fill in the blanks with appropriate words : Pale blue precipitates are formed by ............

To a salt soln 'Y' a small quantity of NH_(4)OH soln. is added slowly & then in excess. A pale blue precipitate is formed which dissolves in excess to form a clear inky blue soln. Identify the positive ion in the salt 'Y'

A metal 'X' normally used for making calorimeters is heated in abundant supply of air until a black coloured residue ' Y' is obtained. This Y reacts with sulphuric acid to form blue coloured salt 'Z'. When to this solution little of ammonium hydroxide was added, pale blue precipitates of 'A' are obtained. This 'A' dissolves in excess of ammonium hydroxide to form a deep blue solution B. Identify the metal X and write the equations for the formation of various compounds i.e., Y, Z, A and B.

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A metal 'X' used to make calorimeters reacts with concentrated nitric acid to form a soluble salt Y. When few drops of ammonium hydroxide are added pale blue precipitates 'Z' are obtained. These precipitates dissolve in excess of ammonium hydroxide to form deep blue solution 'A'. Identify the metal X and give all the chemical equations.

A whiite crystalline salt imparts a violet colour to a Bunsen flame, and with hot concentrated H_(2)SO_(4) , forms a pungent gas. On treatment with an AgNO_(3) solution, this gas forms a white precipitate readily soluble in NH_(3) . The whiite crystalline salt may be:

Which of the following salts does not form any precipitate with excess of NaOH ?

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A metal salt solution forms a yellow precipitate with potassium chromate in acetic acid, a white precipitate with dilute sulphuric acid but does not give precipitate with sodium chloride or iodide. The white precipitate obtained when sodium carbonate is added to the metal salt solution will consist of