Home
Class 11
PHYSICS
A tyre has air pumped at a pressure of 4...

A tyre has air pumped at a pressure of 4 atmosphere at the room temperature `27^(@)C.` If the tyre bursts suddenly calculate the final temperature. `gamma =1.4`

Text Solution

AI Generated Solution

To solve the problem of finding the final temperature of the air in the tire after it bursts, we will follow these steps: ### Step 1: Understand the Initial Conditions - The initial pressure \( P_i = 4 \) atm. - The initial temperature \( T_i = 27^\circ C = 300 \) K (since \( T(K) = T(°C) + 273 \)). - The process is adiabatic because the tire bursts suddenly, meaning no heat is exchanged with the surroundings. ### Step 2: Use the Adiabatic Process Relation ...
Promotional Banner

Topper's Solved these Questions

  • INTERNAL ENERGY

    ICSE|Exercise CONCEPTUAL SHORT ANSWER QUESTIONS WITH ANSWERS |17 Videos
  • INTERNAL ENERGY

    ICSE|Exercise LONG ANSWER QUESTIONS |8 Videos
  • INTERNAL ENERGY

    ICSE|Exercise SOLVED EXAMPLES |9 Videos
  • GRAVITATION

    ICSE|Exercise FROM THE HUBBLE TELESCOP|2 Videos
  • MOTION IN FLUIDS

    ICSE|Exercise SELECTED PROBLEMS (FROM POISEUILLE.S FORMULA) |19 Videos

Similar Questions

Explore conceptually related problems

Four moles of an ideal gas at a pressure of 4 atm and at a temperature of 70^(@)C expands is othermally to four times its initial volume : What is (i) the final temperature and (ii) the final volume ?

The pressure inside a tyre is 4 times that of atmosphere. If the tyre bursts suddenly at temperature. 300 K. What will be the new temperature ?

The gas in a vessel is subjected to a pressure of 20 atmosphere at a temperature 27^(@)C . The pressure of the gas in the vessel after one half of the gas is released from the vessel and the temperature of the remainder is raised by 50^(@)C is

One litre of helium gas at a pressure 76 cm . Of Hg and temperature 27^(@)C is heated till its pressure and volume are double. The final temperature attained by the gas is:

A tyre pumped to a pressure 3.375 atm "at" 27^(@)C suddenly bursts. What is the final temperature (gamma = 1.5) ?

Air (gamma = 1.4 ) is pumped at 2atm pressure in a motor tyre at 20^@C . If the tyre suddenly bursts, what would be the temperature of the air coming out of the tyre. Neglect any mixing with the atmospheric air.

A tyre pumped to a pressure of 3 atmospheres suddenly bursts. Calculate the fall in temperature due to adiabatic expansion. The temperature of air before expansion is 27^(@)C and value of gamma = 1.4 .

A glass bulb can withstand a pressure of 2 atm. It constains air at a temperature of 303 K and at one atmospheric pressure. What is the temperature at which the bulb bursts ? (Neglect the expansion of the bulb) gamma = 1.4

A given mass of air at one atmosphere and 273K is allowed to expand to four times its original volume adiabatically. Calculate the final temperature.

A certain quantity of air is adiabatically compressed so that its pressure increases from 1 atmosphere to 150 atmosphere. If the initial temperature of air is 27^(@)C . Calculate (i) rise in temperature and (ii) the work done of air Y= 1.4).