The efficiency of a cannot's engine is 20%. When the temperature of the source is increased by `25^(@)C,` then its efficiency is found to increase to 25%. Calculate the temperature of source and sink.

Explanation

To solve the problem, we will use the efficiency formula of a Carnot engine and the given conditions to find the temperatures of the source (T1) and the sink (T2).

### Step-by-Step Solution:

1. **Understanding the Efficiency Formula**:
The efficiency (η) of a Carnot engine is given by:
\[
\eta = 1 - \frac{T_2}{T_1}
...