Home
Class 11
PHYSICS
"The efficiency of all real engines are ...

"The efficiency of all real engines are less than that of the carnot engine." Why?

Text Solution

Verified by Experts

Real engines are subjected to the practical difficulties such as friction, heat losses by conduction etc.
Promotional Banner

Topper's Solved these Questions

  • INTERNAL ENERGY

    ICSE|Exercise LONG ANSWER QUESTIONS |8 Videos

  • INTERNAL ENERGY

    ICSE|Exercise SHORT ANSWER QUESTIONS |30 Videos

  • INTERNAL ENERGY

    ICSE|Exercise ADDITIONAL SOLVED PROBLEMS |12 Videos

  • GRAVITATION

    ICSE|Exercise FROM THE HUBBLE TELESCOP|2 Videos

  • MOTION IN FLUIDS

    ICSE|Exercise SELECTED PROBLEMS (FROM POISEUILLE.S FORMULA) |19 Videos

Similar Questions

Explore conceptually related problems

Carnot engine is

The efficiency of carnot engine depends on

In practise, all heat engines have efficiency less than that of a carnot engine because

Assertion: Efficiency of a heat engine can't be greater than efficiency of Carnot engine. Reason: Effieciency of any engine is never 100%

Efficiency of a Carnot heat engine may be given as

The efficiency of a heat engine is defined as the ratio of the mechanical work done by the engine in one cycle to the heat absorbed from the high temperature source . eta = (W)/(Q_(1)) = (Q_(1) - Q_(2))/(Q_(1)) Cornot devised an ideal engine which is based on a reversible cycle of four operations in succession: isothermal expansion , adiabatic expansion. isothermal compression and adiabatic compression. For carnot cycle (Q_(1))/(T_(1)) = (Q_(2))/(T_(2)) . Thus eta = (Q_(1) - Q_(2))/(Q_(1)) = (T_(1) - T_(2))/(T_(1)) According to carnot theorem "No irreversible engine can have efficiency greater than carnot reversible engine working between same hot and cold reservoirs". Efficiency of a carnot's cycle change from (1)/(6) to (1)/(3) when source temperature is raised by 100K . The temperature of the sink is-

Assetion : No engine can have efficiencyt greater than that of the carnot engine Reason : The efficiencyt of a cornot engine is given by eta =1-(T_(2))/(T_(1))

Define thermal efficiency of a heat engine.

The efficiency of carnot's heat engine is 0.5 when the temperature of the source is T_(1) and that of sink is T_(2) .The efficiency of another carnot's heat engine is also 0.5.the temperature of source and sink of the second engine are respecitvely

The maxium possible efficiency of a heat engine is