Angle Bisectors || Two Problems on PA±PB Maximum & Minimum

Angle bisectors| problems

Geometrical Problems OF Maximum and Minimum

Image OF a Line in Given line or (Optics Problem) || PA=PB Maximum & minimum Concept

Geometrical Problem OF Maximum and Minimum

Angle Bisector | Parametric form | Family of lines | Different forms of line | Image of a point in a line based Problems

In the adjoining figure, AB gt AC and the angle bisectors of angleB and angleC meet at point P. Prove that PB gt PC .

Let A-=(3,-4),B-=(1,2) . Let P-=(2k-1+1) be a variable point such that PA+PB is the minimum. Then k is

If A (3,1) and B (-5,7) are any two given points, If P is a point one the line y = x such that PA + PB is minimum then P is

Two circles intersect each other at P and Q. PA and PB are two diameters. Then angleAQB is

The bisector of two adjacent angles in a parallelogram meet at a point P inside the parallelogram. The angle made by these bisectors at a point is ……………………