Intensity in YDSE

YDSE 2

YDSE-1

Minimum thickness of a mica sheet having mu=(3)/(2) which should be placed in front of one of the slits in YDSE is required to reduce the intensity at the centre of screen to half of maximum intensity is

The ratio of intensities at amxima and minima is 25 : 16 . What will be ratio of the widths of two slits in YDSE ?

Statement-1: In YDSE, if a thin film is indroduced in front of the upper slit then the fringe pattern shifts in the downward direction. Statement-2: in YDSE if the slit widths are unequal the minima will be completely dark.

In YDSE, having slits of equal width, let beta be the fringe width and I_(0) be the maximum intensity. At a distance x from the central brigth fringe, the intensity will be

In YDSE experiment a uniform intensity light beam is incident on slit plane which has two slits having width ratio 9 : 4 . Find the ratio of intensities of bright and dark fringes on screen. [25]

In a YDSE experiment, d = 1mm, lambda = 6000Å and D= 1m. The minimum distance between two points on screen having 75% intensity of the maximum intensity will be

Spherical points OF YDSE||Oblique incidence in YDSE||Optical Path