Billet's lens||Fresnel Biprism

YDSE Set up in Medium||Inclined Beam OF Light||YDSE with White Light||Lloyd's Mirror|| Fresnel's Biprism

Lloyd's Mirror||Fresnel's Biprism||Thin film Interference||Newton’s Ring Experiment

If the refracting angle of a Fresnel Biprism is increased, then

When monochromatic light is replaced by white light in Fresnel's biprism arrangement, the central fringe is

In an experiment using Fresnel biprism, fringes of width 0.185 xx 10^(-3)m are observed at a distance of 1 m from the slit. Images are of the coherent sources are then produced at the same distane from the slit by placing a convex lens at a distance of 0.3 m form the slit. The images are found to be separated by 0.7 xx 10^(-2)m . Calculate the wavelength of the light used.

What is the effect on Fresnel's biprism experiment when the use of white light is made?

A parallel coherent beam of fight falls on fresnel biprism of bipism of refractive index mu and angle alpha .The fringe width on a screen at a distance D from biprism will be (wavelength = lambda )

If prism angle alpha=1^@ , mu=1.54 , distance between screen and prism (b)=0.7m , distance between prism and source a=0.3m , lambda=180pi nm then in Fresnel biprism find the value of beta (fringe width).

Interference frings of yellow light of wavelength 6000 A are formed by Billet split lenses. The distance from source to lens is 24 cms. The focal length of lens is 15 cm The lens halves are separated by 0.06 mm. The distance of source to screen is 200 cms. Calculate the fringe width (in mm) Round off the answer to nearest integer.

In Billet's Lens Arrangement, a convex lens of focal length 50 cm is cut along the diameter into two indentical halves Å and B and in the process a layer C of the lens thickness 1 mm is lost. Then the two halves A and B are put together to form a composite lens. Now, infront of this composite lens a source of light emitting wavelength lambda = 6000 Å is placed at a distance of 25 cm as shown in the figure. Behind the lens there is a screen at a distance 50 cm from it. Find the fringe width fo the interference pattern obtained on the screen.