Charged Capacitor Cases||Heat Evolved in Filling/Unfilling Dielectric

The plates of a parallel plate capacitor have on area of 90 cm^(2) each and are separated by 2.5 mm . The capacitor is charged to 400 V. How much electrostatic energy is stored in it ? How much when it is filled with a dielectric medium K = 3 and then charged ? If it is first charged as an air capacitor and then filled with th dielectric, then ?

STATEMENT-1: A parallel plate capacitor is charged by a battery of voltage V . The battery is then disconnected. If the space between the plates is filled with a dielectric, the enegry stroed in the capacitor will decrease STATEMENT-2: The capacitance of a capacitor increases due to the introduciton of a dielectric between the plates.

Capacitor With Dielectric

A capacitor of some capacitance is charged by a 12V battery.Now the space between the plates of capacitors is filled with a dielectric of dielectric constant K=0.5 and again it is charged. The magnitude of the charge will

Two identical capacitors are connected as shown in the figure. A dielectric slab is introduced between the plates of one of the capacitors so as to fill the gap, the battery remaining connected. The charge on each capacitor will be (charge on each condenser is q_(0) , k= dielectric constant). .

The strength of electric filed in the charged and isolated capacitor is decreased when the dielectric slab is inserted. When the dielectric slab is inserted between the plates of a charged capacitor, electricfield produced due to induced charged, opposite to the external field.

Two identical capacitors are connected as shown in fignre. A dielectric slab is introduced between the plates of one of the capacitors so as to fill the gap, the battery remaining connected. What will be the capacitance, the charge, potential difference and stored energy for each capacitor?