Heat Loss||Energy Supplied Battery||Work Done by External Agent

In previous problem, find the work done by external agent.

Find out potential at P and Q due to the two point mass system Find out work done by external agent in bringing unit mass from P to Q Also find work done by gravitational force. .

A ring of mass m_(1) and radius R is fixed in space at some location. An external agent brings a point mass m_(2) from infinity to centre of the ring. Work done by the external agent will be

Two ends A and B of a smooth chain of mass m and length l are situated as shown in figure. If an external agent pulls A till it comes to same level of B, work done by external agent is

STATEMENT-1: Work done by the net force acting on a particle is equal to the change in its kinetic energy. STATEMENT-2: Change in potential energy is always equal to the work done by external forces. STATEMENT-3: Work energy theorem is not applicable, if the work is done by the non-conservative forces

A body of mass 2 kg is moved from a point A to a point B by an external agent in a conservative force field. If the velocity of the body at the points A and B are 5 m//s and 3 m//s respectively and the work done by the external agent is - 10 J, then the change in potential energy between point A and B is

A body of mass 2 kg is moved from a point A to a point B by an external agent in a conservative force field. It the velocity of the body at the points A and B are 5 m/s and 3 m/s respectively and the work done by the external agents is –10 J, then the change in potential energy between points A and B is-

If work done by the system is 300 joule when 100 cal. Heat is supplied to it. The change in internal energy during the process is :-

A capacitor of capacitance 5muF is charged with 5muC charge its capacitance is changed to 2muF by some external agent. The work done by external agent is