General term ( sin^2 theta = sin^2 alpha , cos^2 theta = cos^2 alpha, tan^2 theta= tan^2 alpha)

Solution ( Principle & General Solution ) || General form ( tan theta = tan alpha, cos theta = cos alpha , sin theta = sin alpha)

Prove that (i)sin^(2)theta=sin^(2)alpha;(ii)cos^(2)theta=cos^(2)alpha(iii)tan^(2)theta=tan^(2)alpha

If : cos 2 theta = sin alpha , then : theta is given by

If tan theta=(sin alpha-cos alpha)/(sin alpha+cos alpha) ,then theta is

sin theta+sin2 theta+sin3 theta=sin alpha and cos theta+cos2 theta+cos3 theta=cos alpha then theta is equal to

If sin theta+sin2 theta+sin3 theta=sin alpha and cos theta+cos2 theta+cos3 theta=cos alpha, then theta is equal to

Prove that cos theta =(cos alpha- cos beta)/(1 -cos alpha*cos beta) ⇔ tan theta/2 = pm tan alpha/2 *cot beta/2 .

If tan theta=(sin alpha- cos alpha)/(sin alpha+cos alpha) , then