Parallel Slab

A parallel beam of light is incident on a lens of focal length 10 cm. A parallel slab of refractive index 1.5 and thickness 3 cm is placed on the other side of the lens. Find the distance of the final image from the lens. .

A parallel beam of light is incident on a lens of focal length 10cm. A parallel slab of refractive index 1.5 and thickness 3 cm is placed on the other side of the lens. The nature of the final image from the lens slab combination is: (Assume rays paraxial)

Slabs In Parallel Combination

A parallel glass slab of refractive index sqrt3 is placed in contact with an equilateral prism of refractive index sqrt2 . A ray is incident on left surface of slab as shown. The slab and prism combination is surrounded by air. The magnitude of minimum possible deviation of this ray by slab-prism combination is:

An object lies in front if a thick parallel glass slab, the bottom of which is published if the distance between m first two images formed by bottom surface is 4 cm then find the thickness of the slab [Assume n_(glass) = 3//2 paraxial rays].

The plates of a parallel plate capacitor are separated by a distance d = 1 cm . Two parallel sided dielectric slabs of thickness 0. 7cm and 0.3cm fill the space between the plates. If the dielectric constants of the two slabs are 3 and 5 respectively and a potential difference of 440V is applied across the plates. Find (a) The electric field intensities in each of the slabs. (b) The ratio of electric energies stored in the first to that in the second dielectric slab.

A dielectric slab is placed between the plates of a parallel plate capacitor. Its capacitance

Space between the plates of a parallel plate capacitor is filled with a dielectric slab. The capacitor is charged and then the supply is disconnected to it. If the slab is now taken out then

In a parallel plate capacitor, the region between the plates is filled by a dielectric slab. The capacitor is charged from a cell and then disconnected from it. The slab is now taken out :

- The plates of a parallel plate capacitor are separated by 1cm .Two parallel sided dielectric slabs of thickness 0.6cm and 0.4cm fill the space between the plates.The dielectric constants of the two slabs are 3 and 5 respectively and a potential difference of 210V is applied across the plates.Electric field in the slab of 0.6cm thick is (k)/(-)times10^(4) V/m .The value of 'k is