Lorentz Force

A proton is moving with a velocity of 5 xx 10^(5) m//s along the Y-direction. It is acted upon by an electric field of intensity 10^(5) V/m along the X-direction and a magnetic field of 1 Wb//m^(2) along the Z-direction. Then the Lorentz force on the particle is :

(a) A rod of length is moved horizontally with a uniform velocity 'v' in a direction perpendicular to its length through a region in which a uniform magnetic field is acting vertically downward. Derive the exprwession for the emf induced across the ends of the rod. (b) How does one understand this motional emf by invoking the Lorentz force on the free charge carries of the condutor ? Explain.

A magnetic field B = B_(0) (y//a)(hat)k is into the paper in the +z direction, B_(0) and a are positive constants. A square loop EFGH of side a, mass m and resistance R, in x-y plane, starts falling under the influence of gravity see figure. Note the direction of x and y axis in figure. Find (a) the induced current in the loop and indicate its direction. (b) the total Lorentz force acting on the loop and indicate its direction, and (c) an expression for the speed of the loop, v(t) and its terminal value.

Motional EMF|Motional EMF From Lorentz Froce|Motion Of Straight Conductor In Horizontal Plane|Questions|OMR

Write an expression in a vector form for the Lorentz magnetic force vecF on a charge Q moving with velocity vecV in a magnetic field vecB . What is the direction of the magnetic force?

Lorentz Magnetic Force|Motion Of Moving Charge In Magnetic Field--(Case)I,II,III|Velocity Selector |Moving Coil Galvanometer|Radial Magnetic Field

Write the expression for Lorentz magnetic force on a particle of charges 'q' moving with velocity overset(rightarrow)v in a magnetic field overset(rightarrow)B .